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immpy
Joined: 06 May 2017
Posts: 571
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 Posted: Fri Jan 28, 2022 6:21 pm Post subject: VH+ 012822 |
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Hello all, enjoy the puzzle.
| Code: |
+-------+-------+-------+
| . 5 . | . . . | . 2 . |
| 6 2 . | . 4 . | . 1 5 |
| . . . | 7 5 2 | . . . |
+-------+-------+-------+
| . . 7 | . 3 . | 9 . . |
| . . 2 | 5 9 1 | 4 . . |
| . . 1 | . 8 . | 5 . . |
+-------+-------+-------+
| . . . | 1 6 3 | . . . |
| 2 3 . | . . . | . 5 6 |
| . 1 . | . . . | . 4 . |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site
cheers...immp |
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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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| Posted: Fri Jan 28, 2022 8:23 pm Post subject: |
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| Code: |
+------------+-----------+----------+
| 7 5 349 | 369 1 69 | 8 2 349 |
| 6 2 39 | 389 4 89 | 7 1 5 |
| 1 89 3489 | 7 5 2 | 6 39 349 |
+------------+-----------+----------+
| 5 48 7 | 2 3 46 | 9 68 1 |
| 38 6 2 | 5 9 1 | 4 7 38 |
| 39 49 1 | 46 8 7 | 5 36 2 |
+------------+-----------+----------+
| 4 7 5 | 1 6 3 | 2 89 89 |
| 2 3 89 | 489 7 489 | 1 5 6 |
| 89 1 6 | 89 2 5 | 3 4 7 |
+------------+-----------+----------+
|
Play this puzzle online at the Daily Sudoku site
At this point
If r4c8=6
then stay in c8 gives r3c8 = 9
also stay in r4 gives r3c2 = 9
so we can safely say r4c8 <>6 |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Sun Jan 30, 2022 11:48 am Post subject: |
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| I jumped onto the same chain but at a different point. If you make r3c2 = 9 you get two 9’s in col 2. Or if you complete the loop the starting 9 in r3c2 is evicted by the loop. R3c2 < > 9 |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Sun Jan 30, 2022 11:57 am Post subject: |
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Staying on the cell at r3c2. Whatever value <89> it takes, r4c8 < > 6.
Last edited by Mogulmeister on Sun Jan 30, 2022 12:58 pm; edited 1 time in total |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Sun Jan 30, 2022 12:13 pm Post subject: |
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| Sticking with r3c2 there are pincers for 8 on r3c2 and r4c8 removing 8 from r4c2 |
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immpy
Joined: 06 May 2017
Posts: 571
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| Posted: Sun Jan 30, 2022 5:17 pm Post subject: |
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I used a W-Wing: 9/8 in r3c2,r7c8 connected by 8 in r4c28=>r3c8<>9
cheers...immp |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Sun Jan 30, 2022 7:15 pm Post subject: |
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| Very nice Immp! That r3c2 is a cornerstone on this puzzle! |
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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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| Posted: Mon Jan 31, 2022 7:35 pm Post subject: VH + 012822 |
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| Code: |
+------------------+-----------------+----------------+
| 7 5 349 | 369 1 69 | 8 2 349 |
| 6 2 39 | 389 4 89 | 7 1 5 |
| 1 c89 3489 | 7 5 2 | 6 d39 349 |
+------------------+-----------------+----------------+
| 5 48 7 | 2 3 46 | 9 68 1 |
| 38 6 2 | 5 9 1 | 4 7 38 |
|a39 b49 1 | 46 8 7 | 5 6-3 2 |
+------------------+-----------------+----------------+
| 4 7 5 | 1 6 3 | 2 89 89 |
| 2 3 89 | 489 7 489 | 1 5 6 |
| 89 1 6 | 89 2 5 | 3 4 7 |
+------------------+-----------------+----------------+
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(3=9)r1c6 - r6c2 = r3c2 - (9=3)r3c8 => - 3r6c8; stte |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Mon Jan 31, 2022 8:04 pm Post subject: |
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| Very nice indeed Clement. Good to see you. I think you have a typo first step is r6c1 ? |
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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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| Posted: Mon Jan 31, 2022 8:27 pm Post subject: |
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Another way
if r5c1=3, r6c8=3, r3c8=9, r3c2=8
where does the <8> go in box 4? |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Tue Feb 01, 2022 6:45 am Post subject: |
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| …or extend Clement’s chain by one step so that there are pincers for 3 at (a) and r5c9. |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Tue Feb 01, 2022 4:11 pm Post subject: |
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A slightly odd pincer movement:
(9=6)r1c6-(6=4)r4c6-(4=6)r6c4-(6=3)r6c8-(3=9)r3c8 so r1c9 < > 9
Pincers for 9 at r1c6 and r3c8. |
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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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| Posted: Tue Feb 01, 2022 4:37 pm Post subject: |
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| Mogulmeister wrote: | | Very nice indeed Clement. Good to see you. I think you have a typo first step is r6c1 ? |
Yes you are quite right it was a typo. I was on another forum I am now back. |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Tue Feb 01, 2022 4:40 pm Post subject: |
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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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| Posted: Tue Feb 01, 2022 8:04 pm Post subject: |
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| There is also an XY chain starting at r8c4, if that is 4 then 4-6-3-9-8-4-6-4 puts 4 in r6c4 as well |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Wed Feb 02, 2022 9:41 am Post subject: |
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This is where Eureka can be helpful but I think I understand - you use the 4 in r8c4 to jump onto an xy chain that reverses round Clement's chain but instead of going c to b adds two extra steps going from c via r4c26 to plonk a contradictory 4 in r6c4 ? Two fours in col 4 and r8c4 < > 4 and by implication r6c4 = 4 (< > 6).
Very good.
Strictly speaking - (but who cares really ?) - the xy chain proper starts at r6c4 because the 4 at r8c4 is part of an xyz <489> cell which is the "nudge". Which you don't actually need.
You could use exactly the same chain and start (4=6)r6c4 ("r6c4 not 4 must be 6')
and follow it round to the contradiction (6=4)r6c4 ("r6c4 not 6 must be 4")
So r6c4 = 4 (< > 6). |
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