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Puzzle 11/08/12: ~ Advanced

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daj95376

Joined: 23 Aug 2008
Posts: 3854

Posted: Fri Aug 12, 2011 6:17 pm Post subject: Puzzle 11/08/12: ~ Advanced

Code:

+-----------------------+
| . 7 . | . . . | . . . |
| 2 8 . | . 6 1 | . 7 . |
| . . 4 | . . 2 | . 1 . |
|-------+-------+-------|
| . . . | 1 . 9 | . . 4 |
| . 2 . | . 5 . | . 9 . |
| . 9 1 | 3 . 4 | 6 2 7 |
|-------+-------+-------|
| . . . | . . 3 | . 4 . |
| . 4 2 | . 1 6 | 9 . . |
| . . . | 7 . 8 | . . 1 |
+-----------------------+

Play this puzzle online at the Daily Sudoku site

SudoQ

Joined: 02 Aug 2011
Posts: 127

Posted: Sun Aug 14, 2011 8:05 pm Post subject:

It's a two stepper if you start with this:

Code:

r4c8=5 => r4c7=8 => r4c1<>8
r9c8=5 => r7c9=6 => r7c1=8 => r4c1<>8

Sorry about the syntax, I stil struggle with Eureka!
/SudoQ

daj95376

Joined: 23 Aug 2008
Posts: 3854

Posted: Sun Aug 14, 2011 9:34 pm Post subject:

SudoQ wrote:

Sorry about the syntax, I stil struggle with Eureka!

I was able to follow your logic. That's what's important.

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Mon Aug 15, 2011 12:22 am Post subject:

W-Wing (68), flightless with transport of each pincer; r5c9<>8 M-Wing (56); r1c3<>6

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Mon Aug 15, 2011 12:38 am Post subject:

I just threw this together quickly on Draw/Play.

Code:

+--------------+---------+-------------+
| 1 7 69 | 489 3 5 | 48 68 2 |
| 2 8 359 | 49 6 1 | 345 7 59 |
| 369 356 4 | 89 7 2 | 358 1 569 |
+--------------+---------+-------------+
| 368 36 7 | 1 2 9 | 358 358 4 |
| 4 2 38 | 6 5 7 | 1 9 38 |
| 5 9 1 | 3 8 4 | 6 2 7 |
+--------------+---------+-------------+
| 68 1 568 | 2 9 3 | 7 4 56 |
| 7 4 2 | 5 1 6 | 9 38 38 |
| 369 356 3569 | 7 4 8 | 2 56 1 |
+--------------+---------+-------------+

Play this puzzle online at the Daily Sudoku site

Quote:

r4c8=5 => r4c7=8 => r4c1<>8

Help me, I'm just not seeing how r4c8=5 leads to r4c7=8.

daj95376

Joined: 23 Aug 2008
Posts: 3854

Posted: Mon Aug 15, 2011 1:55 am Post subject:

Marty R. wrote:

Help me, I'm just not seeing how r4c8=5 leads to r4c7=8.

You missed an elimination in r4c7.

Code:

r8 b9 Naked Pair <> 38 r7c9,r9c8
c9 Naked Pair <> 38 r237c9

c7b3 Locked Candidate 1 <> 3 r4c7

after basics
+--------------------------------------------------------------+
| 1 7 69 | 489 3 5 | 48 68 2 |
| 2 8 359 | 49 6 1 | 345 7 59 |
| 369 356 4 | 89 7 2 | 358 1 569 |
|--------------------+--------------------+--------------------|
| 368 36 7 | 1 2 9 | 58 358 4 |
| 4 2 38 | 6 5 7 | 1 9 38 |
| 5 9 1 | 3 8 4 | 6 2 7 |
|--------------------+--------------------+--------------------|
| 68 1 568 | 2 9 3 | 7 4 56 |
| 7 4 2 | 5 1 6 | 9 38 38 |
| 369 356 3569 | 7 4 8 | 2 56 1 |
+--------------------------------------------------------------+
# 42 eliminations remain

Another way to present SudoQ's logic:

Code:

if r4c7<>8
then r4c7= 5
then r4c8<>5
then r9c8= 5
then r7c9<>5
then r7c9= 6
then r7c1<>6
then r7c1= 8 => r4c1<>8

As an AIC:

Code:

(8=5)r4c7 - (5)r4c8 = (5)r9c8 - (5=6)r7c9 - (6=8)r7c1 => r4c1<>8

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Mon Aug 15, 2011 3:46 am Post subject:

Quote:

You missed an elimination in r4c7.

Thanks.

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