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daj95376
Joined: 23 Aug 2008
Posts: 3854
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 Posted: Sun Jul 17, 2011 3:57 pm Post subject: Puzzle 11/07/17: ~ XY |
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| Code: | +-----------------------+
| 4 . 3 | . . 5 | 6 7 . |
| . . 2 | . . . | 3 5 . |
| 5 1 8 | . . . | 2 9 4 |
|-------+-------+-------|
| . . . | 7 . . | 1 . 3 |
| . . . | . . . | . . 5 |
| 3 . . | . . 8 | . 2 . |
|-------+-------+-------|
| 2 5 7 | 3 . . | . 1 . |
| 1 3 6 | . . 9 | 7 . . |
| . . 4 | 1 2 . | . . 6 |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Mon Jul 18, 2011 4:51 am Post subject: |
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Hidden UR (49); r5c7<>4, r6c4<>9
DP (68), boxes 46. R5c1=7 or r45c8=4; common outcome; r4c8<>8
Type 1 UR (67); r5c2<>67
XY-Wing (584), flightless with transport; r6c2<>4 |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Mon Jul 18, 2011 1:50 pm Post subject: |
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Marty, I believe that your first step is a one-stepper when viewed differently.........
(5=9)r4c3-(9=1)r5c3-(1=26)r45c6-(6=4)r7c6-(4=8)r7c7-aur(49)r56c47[(8)r5c7=(5)r6c4]; r6c3<>5
Ted |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Mon Jul 18, 2011 4:24 pm Post subject: |
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My solver's solution reduces to two steps:
| Code: | +--------------------------------------------------------------+
| 4 9 3 | 2 *18 5 | 6 7 *18 |
| 67 67 2 | 89 *18+49 14 | 3 5 *18 |
| 5 1 8 | 6 7 3 | 2 9 4 |
|--------------------+--------------------+--------------------|
| 68 246 59 | 7 59 26 | 1 468 3 |
| 678 2467 19 | 49 3 126 | 489 468 5 |
| 3 46 159 | 459 16 8 | 49 2 7 |
|--------------------+--------------------+--------------------|
| 2 5 7 | 3 468 46 | 48 1 9 |
| 1 3 6 | 58 458 9 | 7 48 2 |
| 9 8 4 | 1 2 7 | 5 3 6 |
+--------------------------------------------------------------+
# 46 eliminations remain
r12c59 <18> UR Type 1.2224 <> 18 r2c5
XY-Chain: (1=4)r2c6 - (4=9)r2c5 - (9=5)r4c5 - (5=9)r4c3 - (9=1)r5c3 => r5c6<>1
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Which can be treated as a single-stepper:
| Code: |
(1=4)r2c6 - (4=UR=9)r2c5 - (9=5)r4c5 - (5=9)r4c3 - (9=1)r5c3 => r5c6<>1
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This is a perspective on a UR Type 1 that I hadn't considered previously. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Mon Jul 18, 2011 4:35 pm Post subject: |
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| tlanglet wrote: | Marty, I believe that your first step is a one-stepper when viewed differently.........
(5=9)r4c3-(9=1)r5c3-(1=26)r45c6-(6=4)r7c6-(4=8)r7c7-aur(49)r56c47[(8)r5c7=(5)r6c4]; r6c3<>5
Ted |
Ted, I am more than capable of turning a one-stepper into a four-stepper; I've done it many times. However, I don't understand Eureka so I don't know what your one-stepper is. |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Mon Jul 18, 2011 8:28 pm Post subject: |
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| daj95376 wrote: | My solver's solution reduces to two steps:
| Code: | +--------------------------------------------------------------+
| 4 9 3 | 2 *18 5 | 6 7 *18 |
| 67 67 2 | 89 *18+49 14 | 3 5 *18 |
| 5 1 8 | 6 7 3 | 2 9 4 |
|--------------------+--------------------+--------------------|
| 68 246 59 | 7 59 26 | 1 468 3 |
| 678 2467 19 | 49 3 126 | 489 468 5 |
| 3 46 159 | 459 16 8 | 49 2 7 |
|--------------------+--------------------+--------------------|
| 2 5 7 | 3 468 46 | 48 1 9 |
| 1 3 6 | 58 458 9 | 7 48 2 |
| 9 8 4 | 1 2 7 | 5 3 6 |
+--------------------------------------------------------------+
# 46 eliminations remain
r12c59 <18> UR Type 1.2224 <18> r5c6<1> r5c6<>1
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This is a perspective on a UR Type 1 that I hadn't considered previously. |
Danny, that is very cool  . It is something I definitely have not thought about before although I once used a Type 2 pattern to link.
Ted |
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peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
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| Posted: Tue Jul 19, 2011 9:36 am Post subject: |
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Here's a simple als one stepper..
| Code: | | (8=5)r8c4 - ant(5=469)r6c247 - (6)r6c5=r7c5 ; r7c5<>8 |
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