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		daj95376
 
 
  Joined: 23 Aug 2008 Posts: 3854
 
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				 Posted: Sat Nov 08, 2008 6:45 pm    Post subject: VH: Set A Puzzle 22 | 
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				 	  | Code: | 	 		   +-----------------------+
 
 | 7 . 8 | 9 3 . | 2 5 . |
 
 | . . . | . 5 . | 4 8 . |
 
 | 2 . . | . . 4 | 1 9 . |
 
 |-------+-------+-------|
 
 | 9 . . | 8 . . | . . . |
 
 | 1 8 . | . 9 . | . . . |
 
 | . . 3 | . . 7 | 8 . . |
 
 |-------+-------+-------|
 
 | 8 7 4 | . . 9 | 3 . . |
 
 | 3 2 1 | . . . | . . . |
 
 | . . . | . . . | . . . |
 
 +-----------------------+
 
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		Asellus
 
 
  Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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				 Posted: Sun Nov 09, 2008 1:39 am    Post subject:  | 
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				| I needed 2 steps without XY(Z) Wings/Chains. | 
			 
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		arkietech
 
 
  Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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				 Posted: Sun Nov 09, 2008 3:19 am    Post subject:  | 
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				here is a nice one step
 
 	  | Code: | 	 		   *--------------------------------------------------*
 
 | 7    4    8    | 9    3    1    | 2    5    6    |
 
 | 6    1    9    | 7    5    2    | 4    8    3    |
 
 | 2    3    5    | 6    8    4    | 1    9    7    |
 
 |----------------+----------------+----------------|
 
 | 9    56   2    | 8    14   3    | 56   7    14   |
 
 | 1    8    7    | 24   9    56   | 56   3    24   |
 
 | 4    56   3    | 125  126  7    | 8    12   9    |
 
 |----------------+----------------+----------------|
 
 | 8    7    4    | 12   126  9    | 3    126  5    |
 
 | 3    2    1    | 45   7    56   | 9    46   8    |
 
 | 5    9    6    | 3    124  8    | 7    124  12   |
 
 *--------------------------------------------------*
 
r8c8=4=r9c8=1=r9c9=2=r5c9=4=r5c4=4=r8c4=4=r8c8=>r8c8=4 | 	 
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		daj95376
 
 
  Joined: 23 Aug 2008 Posts: 3854
 
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				 Posted: Sun Nov 09, 2008 3:42 am    Post subject:  | 
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				 	  | arkietech wrote: | 	 		  here is a nice one step
 
 
r8c8=4=r9c8=1=r9c9 | 	  
 
It seems to me that the deduction in red is incorrect. There are two alternate choices for (1) in [b9]/[r9]. | 
			 
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		Asellus
 
 
  Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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				 Posted: Sun Nov 09, 2008 4:50 am    Post subject:  | 
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				It is possible to remove <1> from r7c8 (I won't say how except that it's not a chain).  Then, arkietech's loop works via r6c8 rather than r9c9 ... though that's not how I solved it.
 
 
Also, shouldn't it be "[r5c4]-4-[r8c4]"?  (I find Eureka notation less confusing.) | 
			 
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